I was trying to convert all the shp in a folder into kml.
featureclasses = arcpy.ListFeatureClasses()
for fc in featureclasses:
# Set Local Variables
composite = 'COMPOSITE'
pixels = 1024
dpi = 96
clamped = 'CLAMPED_TO_GROUND'
scale = 1
outKML = fc[:-4] + ".kmz"
arcpy.LayerToKML_conversion(fc,outKML, scale, composite,'', pixels, dpi, clamped)
It always says Failed to execute. Parameters are not valid. ERROR 000732: Layer: Dataset ZZZ.shp does not exist or is not supported Failed to execute (LayerToKML).
But I can manually do it within ArcMap 10.1 Desktop...
Answer
This is because the Layer to KML tool takes either LAYERS (feature layers in a map for example), or LAYER FILES (.lyr files on disk pointing at featureclasses).
If you want to run this as a script outside of ArcMap you'll have to run MakeFeatureLayer on every shapefile, turning them into a layer first and pass that onto Layer to KML.
This is starter code...you'll have to modify it to make unique names. As-is it'll overwrite each KMZ it outputs.
featureclasses = arcpy.ListFeatureClasses()
for fc in featureclasses:
arcpy.MakeFeatureLayer_management(fc, "name1")
arcpy.LayerToKML_conversion("name1", r"c:\temp\foo1.kmz")
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